What is the radius sqrt(25)=(x+1)^2+(y-3)^2 ?

The radius sqrt(25)=(x+1)^2+(y-3)^2 is r=sqrt(5)

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radius sqrt(25)=(x+1)^2+(y-3)^2

radius

25 = (x + 1)^{2} + (y - 3)^{2}

r = 5

Solution steps

25 = (x + 1)^{2} + (y - 3)^{2}

Rewrite

25 = (x + 1)^{2} + (y - 3)^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 5

And the radius is:

r = 5

(x - 2)^{2} + y^{2} = 16

x^{2} + y^{2} - 4 x - 8 y + 18 = 0

3 x^{2} + 3 y^{2} + 6 x - 5 y = 0

(x + 2)^{2} + (y - 5)^{2} = 25

(x + \frac{1}{3})^{2} + (y - 5)^{2} = 7

What is the radius sqrt(25)=(x+1)^2+(y-3)^2 ?
The radius sqrt(25)=(x+1)^2+(y-3)^2 is r=sqrt(5)