What is the radius x^2-8x+y^2+6y=-9 ?

The radius x^2-8x+y^2+6y=-9 is r=4

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radius x^2-8x+y^2+6y=-9

radius

x^{2} - 8 x + y^{2} + 6 y = - 9

r = 4

Solution steps

x^{2} - 8 x + y^{2} + 6 y = - 9

Rewrite

x^{2} - 8 x + y^{2} + 6 y = - 9

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (4, - 3), r = 4

And the radius is:

r = 4

(x + 1)^{2} + (y - 5)^{2} = 5^{2}

x^{2} + y^{2} - 13 = 0

(x + \frac{7}{2})^{2} + (y - \frac{1}{2})^{2} = 5

4 x^{2} + 4 y^{2} - 3 x + 5 y - 5 = 0

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1