What is the radius x^2+y^2+14x-18y+81=0 ?

The radius x^2+y^2+14x-18y+81=0 is r=7

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radius x^2+y^2+14x-18y+81=0

radius

x^{2} + y^{2} + 14 x - 18 y + 81 = 0

r = 7

Solution steps

x^{2} + y^{2} + 14 x - 18 y + 81 = 0

Rewrite

x^{2} + y^{2} + 14 x - 18 y + 81 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 9)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, 9), r = 7

And the radius is:

r = 7

x^{2} + y^{2} - 2 x - 16 y + 40 = 0

y^{2} + 4 x - 20 - 2 y = - x^{2}

(x + 12)^{2} + (y - 9)^{2} = 35

(x - 4)^{2} + (y + 1)^{2} = 16

x^{2} + 6 x + y^{2} - 3 y = - \frac{1}{4}

What is the radius x^2+y^2+14x-18y+81=0 ?
The radius x^2+y^2+14x-18y+81=0 is r=7