What is the radius 5x^2+5y^2+10x+2y+3=0 ?

The radius 5x^2+5y^2+10x+2y+3=0 is r=(sqrt(11))/5

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radius 5x^2+5y^2+10x+2y+3=0

radius

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

r = \frac{11}{5}

Solution steps

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

Rewrite

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- \frac{1}{5}))^{2} = (\frac{11}{5})^{2}

Therefore the circle properties are:

(a, b) = (- 1, - \frac{1}{5}), r = \frac{11}{5}

And the radius is:

r = \frac{11}{5}

x^{2} + y^{2} = 48

x^{2} + y^{2} - x + 6 y + 9 = 0

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}

x^{2} + y^{2} - 6 x + 2 y = 6

x^{2} + y^{2} - 6 x - 10 y + 9 = 0

What is the radius 5x^2+5y^2+10x+2y+3=0 ?
The radius 5x^2+5y^2+10x+2y+3=0 is r=(sqrt(11))/5