What is the radius 2x^2+2y^2+10x=2y+7 ?

The radius 2x^2+2y^2+10x=2y+7 is r=sqrt(10)

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radius 2x^2+2y^2+10x=2y+7

radius

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

r = 10

Solution steps

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

Rewrite

2 x^{2} + 2 y^{2} + 10 x = 2 y + 7

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{1}{2})^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = 10

And the radius is:

r = 10

x^{2} + y^{2} - 16 y + 39 = 0

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

x^{2} + y^{2} + 8 y = 2 x + 20

(x - 2)^{2} + (y - 5)^{2} = 49

x^{2} - 6 x + y^{2} = 7

What is the radius 2x^2+2y^2+10x=2y+7 ?
The radius 2x^2+2y^2+10x=2y+7 is r=sqrt(10)