What is the radius 2x^2+2y^2+8x-12y-26=0 ?

The radius 2x^2+2y^2+8x-12y-26=0 is r=sqrt(26)

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radius 2x^2+2y^2+8x-12y-26=0

radius

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

r = 26

Solution steps

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

Rewrite

2 x^{2} + 2 y^{2} + 8 x - 12 y - 26 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 26

And the radius is:

r = 26

x^{2} + y^{2} + 10 x - 8 y + 25 = 0

x^{2} + y^{2} + 3 x - 4 y - 15 = 0

(x + 6)^{2} + y^{2} = 1

(x + 2)^{2} + (y - 6)^{2} = 169

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5) 6

What is the radius 2x^2+2y^2+8x-12y-26=0 ?
The radius 2x^2+2y^2+8x-12y-26=0 is r=sqrt(26)