What is the radius x^2+y^2-8x+18y+16=0 ?

The radius x^2+y^2-8x+18y+16=0 is r=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2-8x+18y+16=0

radius

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

r = 9

Solution steps

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

Rewrite

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 9))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (4, - 9), r = 9

And the radius is:

r = 9

(x - 1)^{2} + (y + 4)^{2} = 16

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

x^{2} + y^{2} - 2 x - 6 y = 71

2 x^{2} + 2 y^{2} - 3 x + 4 y - 35 = 0

(x - 5)^{2} + (y - 3)^{2} = 64