What is the radius x^2+y^2+10y+15=0 ?

The radius x^2+y^2+10y+15=0 is r=sqrt(10)

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radius x^2+y^2+10y+15=0

radius

x^{2} + y^{2} + 10 y + 15 = 0

r = 10

Solution steps

x^{2} + y^{2} + 10 y + 15 = 0

Rewrite

x^{2} + y^{2} + 10 y + 15 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 5))^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (0, - 5), r = 10

And the radius is:

r = 10

6 x^{2} + 6 y^{2} + 12 x - y = 0

x^{2} + y^{2} + 10 x - 16 y = - 80

(x + 2)^{2} + (y - 1)^{2} = 16

(x - 3)^{2} + (y - 1)^{2} = 4

(x + 0)^{2} + (y - 0)^{2} = 22