What is the radius 5x^2+5y^2-60x+30y-25=0 ?

The radius 5x^2+5y^2-60x+30y-25=0 is r=5sqrt(2)

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radius 5x^2+5y^2-60x+30y-25=0

radius

5 x^{2} + 5 y^{2} - 60 x + 30 y - 25 = 0

r = 52

Solution steps

5 x^{2} + 5 y^{2} - 60 x + 30 y - 25 = 0

Rewrite

5 x^{2} + 5 y^{2} - 60 x + 30 y - 25 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 3))^{2} = (52)^{2}

Therefore the circle properties are:

(a, b) = (6, - 3), r = 52

And the radius is:

r = 52

2 x^{2} + 2 y^{2} + 28 x - 8 y + 4 = 0

4 x^{2} + 4 y^{2} = 144

2 x^{2} + 2 y^{2} - 4 x + 12 y - 24 = 0

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

(x + 2)^{2} + y^{2} = 9

What is the radius 5x^2+5y^2-60x+30y-25=0 ?
The radius 5x^2+5y^2-60x+30y-25=0 is r=5sqrt(2)