What is the radius (x-2)^2+(y-1)^2=49 ?

The radius (x-2)^2+(y-1)^2=49 is r=7

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radius (x-2)^2+(y-1)^2=49

radius

(x - 2)^{2} + (y - 1)^{2} = 49

r = 7

Solution steps

(x - 2)^{2} + (y - 1)^{2} = 49

Rewrite

(x - 2)^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 7

And the radius is:

r = 7

2 (x + 1)^{2} + 2 (y - 3)^{2} = 5

x^{2} - 3 x + y^{2} + 3 y - 5 = 0

x^{2} + y^{2} - 14 x + 2 y + 14 = 0

x^{2} + y^{2} + 8 x - 2 y + 15 = 0

(x + 5)^{2} + y^{2} = 4