What is the radius x^2+2x+y^2-6y=0 ?

The radius x^2+2x+y^2-6y=0 is r=sqrt(10)

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radius x^2+2x+y^2-6y=0

radius

x^{2} + 2 x + y^{2} - 6 y = 0

r = 10

Solution steps

x^{2} + 2 x + y^{2} - 6 y = 0

Rewrite

x^{2} + 2 x + y^{2} - 6 y = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 10

And the radius is:

r = 10

x^{2} + y^{2} - 6 x + 6 y + 2 = 0

x^{2} + y^{2} - 4 x + 8 y + 19 = 0

x^{2} + y^{2} = 125

x^{2} + y^{2} - 4 x + 8 y + 11 = 0

4 x^{2} + 4 y^{2} - x + 2 y - 11 = 0