What is the radius x^2+y^2=sqrt(4) ?

The radius x^2+y^2=sqrt(4) is r=sqrt(\sqrt{4)}

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radius x^2+y^2=sqrt(4)

radius

x^{2} + y^{2} = 4

r = 4

Solution steps

x^{2} + y^{2} = 4

Rewrite

x^{2} + y^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (4)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 8 x - 6 y + 24 = 0

2 x^{2} + 2 y^{2} + 16 x - 6 y - 18 = 0

(x - (- 5))^{2} + (y - 7)^{2} = 3^{2}

(x + 6)^{2} + (y - 1)^{2} = 16

x^{2} + y^{2} - 7 x = 15 - 2 y

What is the radius x^2+y^2=sqrt(4) ?
The radius x^2+y^2=sqrt(4) is r=sqrt(\sqrt{4)}