What is the radius 2x^2+2y^2+44x+28y=52 ?

The radius 2x^2+2y^2+44x+28y=52 is r=14

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radius 2x^2+2y^2+44x+28y=52

radius

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

r = 14

Solution steps

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

Rewrite

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

in the form of the standard circle equation

(x - (- 11))^{2} + (y - (- 7))^{2} = 1 4^{2}

Therefore the circle properties are:

(a, b) = (- 11, - 7), r = 14

And the radius is:

r = 14

x^{2} + y^{2} + 4 x + 2 y - 11 = 0

(x - 15)^{2} + (y + 20)^{2} = 81

(x - 2)^{2} + (y + 1)^{2} = 16

x^{2} + y^{2} - 8 x + 4 y + 16 = 0

74 = (24 - x)^{2} + (22 - y)^{2}

What is the radius 2x^2+2y^2+44x+28y=52 ?
The radius 2x^2+2y^2+44x+28y=52 is r=14