What is the radius x^2+y^2-2x-10y+17=0 ?

The radius x^2+y^2-2x-10y+17=0 is r=3

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radius x^2+y^2-2x-10y+17=0

radius

x^{2} + y^{2} - 2 x - 10 y + 17 = 0

r = 3

Solution steps

x^{2} + y^{2} - 2 x - 10 y + 17 = 0

Rewrite

x^{2} + y^{2} - 2 x - 10 y + 17 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, 5), r = 3

And the radius is:

r = 3

(x + 5)^{2} + (y + 1)^{2} = 16

x^{2} + (y + 5)^{2} = 7

3 (x + 1)^{2} + 3 (y - 1)^{2} = 6

x^{2} + y^{2} - 10 x - 6 y = 30

(x - 1)^{2} + (y + 3)^{2} = 16