What is the radius x^2+y^2-16x+8y+79=0 ?

The radius x^2+y^2-16x+8y+79=0 is r=1

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radius x^2+y^2-16x+8y+79=0

radius

x^{2} + y^{2} - 16 x + 8 y + 79 = 0

r = 1

Solution steps

x^{2} + y^{2} - 16 x + 8 y + 79 = 0

Rewrite

x^{2} + y^{2} - 16 x + 8 y + 79 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 4))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (8, - 4), r = 1

And the radius is:

r = 1

x^{2} + 8 x + y^{2} - 2 y = 9

x^{2} + y^{2} + 12 y - 108 = 0

x^{2} + 6 x + y^{2} - 2 y - 15 = 0

x^{2} + y^{2} - 8 x + 10 y - 8 = 0

X^{2} + Y^{2} = 49