What is the radius (x-1/2)^2+(y-1/2)^2= 9/4 ?

The radius (x-1/2)^2+(y-1/2)^2= 9/4 is r= 3/2

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radius (x-1/2)^2+(y-1/2)^2= 9/4

radius

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

r = \frac{3}{2}

Solution steps

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

Rewrite

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

And the radius is:

r = \frac{3}{2}

+ x^{2} + y^{2} - 4 x = 0

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

x^{2} + y^{2} + 2 x - 4 y - 4 = 0

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

x^{2} + y^{2} - 4 x + 9 x = 16

What is the radius (x-1/2)^2+(y-1/2)^2= 9/4 ?
The radius (x-1/2)^2+(y-1/2)^2= 9/4 is r= 3/2