What is the radius (x+5)^2+(y-2)^2=25 ?

The radius (x+5)^2+(y-2)^2=25 is r=5

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radius (x+5)^2+(y-2)^2=25

radius

(x + 5)^{2} + (y - 2)^{2} = 25

r = 5

Solution steps

(x + 5)^{2} + (y - 2)^{2} = 25

Rewrite

(x + 5)^{2} + (y - 2)^{2} = 25

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 5

And the radius is:

r = 5

x^{2} + (y - 4)^{2} = 1

x^{2} + (y - 4)^{2} = 4

x^{2} + y^{2} + 9 x - 9 y - 17 = 0

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

x^{2} + y^{2} + 8 x - 6 y = 6