What is the radius (x-5)^2+(y-12)^2=9 ?

The radius (x-5)^2+(y-12)^2=9 is r=3

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radius (x-5)^2+(y-12)^2=9

radius

(x - 5)^{2} + (y - 12)^{2} = 9

r = 3

Solution steps

(x - 5)^{2} + (y - 12)^{2} = 9

Rewrite

(x - 5)^{2} + (y - 12)^{2} = 9

in the form of the standard circle equation

(x - 5)^{2} + (y - 12)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, 12), r = 3

And the radius is:

r = 3

4 x^{2} + 4 y^{2} - 16 = 0

3 (x - 5)^{2} + 3 y^{2} = 27

x^{2} + y^{2} + 12 y = - 32

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

(x + 2)^{2} + (y - 4)^{2} = 9