What is the radius (x-2)^2+(y+3)^2=16 ?

The radius (x-2)^2+(y+3)^2=16 is r=4

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radius (x-2)^2+(y+3)^2=16

radius

(x - 2)^{2} + (y + 3)^{2} = 16

r = 4

Solution steps

(x - 2)^{2} + (y + 3)^{2} = 16

Rewrite

(x - 2)^{2} + (y + 3)^{2} = 16

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 4

And the radius is:

r = 4

(x - 1)^{2} + (y - 3)^{2} = 49

364 + 28 y + y^{2} + x^{2} = - 26 x

(x - 6)^{2} + (y - 4)^{2} = 25

x^{2} + y^{2} + 6 x - 2 y - 8 = 0

x^{2} + y^{2} + 2 x + 4 y - 20 = 0