What is the radius (x-2)^2+(y-(-5))^2=sqrt(97) ?

The radius (x-2)^2+(y-(-5))^2=sqrt(97) is r=sqrt(\sqrt{97)}

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radius (x-2)^2+(y-(-5))^2=sqrt(97)

radius

(x - 2)^{2} + (y - (- 5))^{2} = 97

r = 97

Solution steps

(x - 2)^{2} + (y - (- 5))^{2} = 97

Rewrite

(x - 2)^{2} + (y - (- 5))^{2} = 97

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = (97)^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = 97

And the radius is:

r = 97

(x - 5)^{2} + y^{2} = 9

x^{2} - 4 x + 12 y + y^{2} + 14 = 0

x^{2} + y^{2} - 16 x - 4 = 0

x^{2} - 8 x - 2 y + y^{2} = 8

x^{2} + 10 x - 14 y + y^{2} = 26

What is the radius (x-2)^2+(y-(-5))^2=sqrt(97) ?
The radius (x-2)^2+(y-(-5))^2=sqrt(97) is r=sqrt(\sqrt{97)}