What is the circumference 3x^2+3y^2+2x-4y-1=0 ?

The circumference 3x^2+3y^2+2x-4y-1=0 is C=(4sqrt(2)pi)/3

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circumference 3x^2+3y^2+2x-4y-1=0

circumference

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

C = \frac{4 2 π}{3}

Solution steps

C = 2 π r

Find the radius

Radius given

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0 : r = \frac{2 2}{3}

C = 2 π \frac{2 2}{3}

Refine

C = \frac{4 2 π}{3}

x^{2} + y^{2} = 25

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

x^{2} + y^{2} = 7

x^{2} + y^{2} - 6 x + 8 y = 144

What is the circumference 3x^2+3y^2+2x-4y-1=0 ?
The circumference 3x^2+3y^2+2x-4y-1=0 is C=(4sqrt(2)pi)/3