What is the circumference+x^2+y^2+8x+4y-3=40 ?

The circumference+x^2+y^2+8x+4y-3=40 is C=6sqrt(7)pi

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circumference+x^2+y^2+8x+4y-3=40

circumference

+ x^{2} + y^{2} + 8 x + 4 y - 3 = 40

C = 67 π

Solution steps

C = 2 π r

Find the radius

Radius given

+ x^{2} + y^{2} + 8 x + 4 y - 3 = 40 : r = 37

C = 2 π 37

Refine

C = 67 π

x^{2} + y^{2} = 81

y^{2} = 4 - x^{2}

x^{2} + y^{2} + 4 x - 6 y + 12 = 0

(x - 2)^{2} + (y + 6)^{2} = 16

x^{2} - 12 x + y^{2} - 8 y = 6

What is the circumference+x^2+y^2+8x+4y-3=40 ?
The circumference+x^2+y^2+8x+4y-3=40 is C=6sqrt(7)pi