What is the circumference (x+6)^2+(y+5)^2=8 ?

The circumference (x+6)^2+(y+5)^2=8 is C=4sqrt(2)pi

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circumference (x+6)^2+(y+5)^2=8

circumference

(x + 6)^{2} + (y + 5)^{2} = 8

C = 42 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 6)^{2} + (y + 5)^{2} = 8 : r = 8

C = 2 π 8

Refine

C = 42 π

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

x^{2} + y^{2} = 5

3 x^{2} + 3 y^{2} + 4 y - 7 = 0

x^{2} + y^{2} + 4 x + 12 y - 100 = 0

x^{2} + y^{2} - 6 x + 4 y + 8 = 0

What is the circumference (x+6)^2+(y+5)^2=8 ?
The circumference (x+6)^2+(y+5)^2=8 is C=4sqrt(2)pi