What is the circumference x^2+y^2-4x+10y+13=0 ?

The circumference x^2+y^2-4x+10y+13=0 is C=8pi

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circumference x^2+y^2-4x+10y+13=0

circumference

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 4 x + 10 y + 13 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

X^{2} + 4 X + Y^{2} - 6 Y + 9 = 0

x^{2} + y^{2} - 4 x - 4 y = 0

x^{2} + (y - 2)^{2} = 1

x^{2} + 2 x + y^{2} = 8

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

What is the circumference x^2+y^2-4x+10y+13=0 ?
The circumference x^2+y^2-4x+10y+13=0 is C=8pi