What is the circumference x^2+y^2+8x-2y+15=0 ?

The circumference x^2+y^2+8x-2y+15=0 is C=2sqrt(2)pi

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circumference x^2+y^2+8x-2y+15=0

circumference

x^{2} + y^{2} + 8 x - 2 y + 15 = 0

C = 22 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 8 x - 2 y + 15 = 0 : r = 2

C = 22 π

3 x^{2} + 3 y^{2} - 12 x + 6 y - 12 = 0

x^{2} - 4 x + y^{2} + 8 y - 5 = 0

3 x^{2} + 3 y^{2} = 75

5 x^{2} + 5 y^{2} - 25 = 0

x^{2} + y^{2} - 4 x - 6 y - 3 = 0

What is the circumference x^2+y^2+8x-2y+15=0 ?
The circumference x^2+y^2+8x-2y+15=0 is C=2sqrt(2)pi