What is the circumference (x+3)^2+(y-2)^2= 9/4 ?

The circumference (x+3)^2+(y-2)^2= 9/4 is C=3pi

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circumference (x+3)^2+(y-2)^2= 9/4

circumference

(x + 3)^{2} + (y - 2)^{2} = \frac{9}{4}

C = 3 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 3)^{2} + (y - 2)^{2} = \frac{9}{4} : r = \frac{3}{2}

C = 2 π \frac{3}{2}

Refine

C = 3 π

(x - 2)^{2} + (y - 9)^{2} = 1 6^{2}

x^{2} + y^{2} + 6 x - 4 y - 51 = 0

x^{2} + y^{2} - 4 x - 6 y + 9 = 0

x^{2} + y^{2} + 4 y - 4 = 0

x^{2} + y^{2} - 4 x - 12 = 0

What is the circumference (x+3)^2+(y-2)^2= 9/4 ?
The circumference (x+3)^2+(y-2)^2= 9/4 is C=3pi