What is the circumference (x-2)^2+(y-5)^2=16 ?

The circumference (x-2)^2+(y-5)^2=16 is C=8pi

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circumference (x-2)^2+(y-5)^2=16

circumference

(x - 2)^{2} + (y - 5)^{2} = 16

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 2)^{2} + (y - 5)^{2} = 16 : r = 4

C = 2 π 4

Refine

C = 8 π

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

x^{2} + y^{2} = 2.5

4 x - x^{2} - y^{2} - 6 y - 2 \geq 0

x^{2} + y^{2} + 2 x - 2 y = 0

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

What is the circumference (x-2)^2+(y-5)^2=16 ?
The circumference (x-2)^2+(y-5)^2=16 is C=8pi