What is the circumference x^2+y^2+6x-4y-12=0 ?

The circumference x^2+y^2+6x-4y-12=0 is C=10pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2+6x-4y-12=0

circumference

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 6 x - 4 y - 12 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} + 2 x + 2 y - 2 = 0

(x - \frac{1}{2})^{2} + (y + \frac{2}{3})^{2} = 5

2 (x - 3)^{2} + 2 y^{2} = 8

x^{2} + y^{2} \leq 25

(x + 6)^{2} + (y - 7)^{2} = 9

What is the circumference x^2+y^2+6x-4y-12=0 ?
The circumference x^2+y^2+6x-4y-12=0 is C=10pi