What is the circumference 2x^2+2y^2+x+y=0 ?

The circumference 2x^2+2y^2+x+y=0 is C= pi/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference 2x^2+2y^2+x+y=0

circumference

2 x^{2} + 2 y^{2} + x + y = 0

C = \frac{π}{2}

Solution steps

C = 2 π r

Find the radius

Radius given

2 x^{2} + 2 y^{2} + x + y = 0 : r = \frac{1}{2 2}

C = 2 π \frac{1}{2 2}

Refine

C = \frac{π}{2}

5 x^{2} + 5 y^{2} - 30 y - 5 = 0

x^{2} + y^{2} + 5 y = 12

(x - 2)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 6 x + 2 y - 6 = 0

(x)^{2} + (y - 2)^{2} = 9

What is the circumference 2x^2+2y^2+x+y=0 ?
The circumference 2x^2+2y^2+x+y=0 is C= pi/(sqrt(2))