What is the circumference (x+2)^2+(y-2)^2=13 ?

The circumference (x+2)^2+(y-2)^2=13 is C=2sqrt(13)pi

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circumference (x+2)^2+(y-2)^2=13

circumference

(x + 2)^{2} + (y - 2)^{2} = 13

C = 213 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 2)^{2} + (y - 2)^{2} = 13 : r = 13

C = 213 π

x^{2} + y^{2} = 121

(x - 3)^{2} + (y + 2)^{2} = 10

(x - 4)^{2} + (y - 1)^{2} = 4

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

(x - 3)^{2} + (y - 5)^{2} = 25

What is the circumference (x+2)^2+(y-2)^2=13 ?
The circumference (x+2)^2+(y-2)^2=13 is C=2sqrt(13)pi