What is the circumference 2x^2+2y^2-24x+28y+120=0 ?

The circumference 2x^2+2y^2-24x+28y+120=0 is C=10pi

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circumference 2x^2+2y^2-24x+28y+120=0

circumference

2 x^{2} + 2 y^{2} - 24 x + 28 y + 120 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

2 x^{2} + 2 y^{2} - 24 x + 28 y + 120 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} = 17

x^{2} + y^{2} = 13

(x - 0)^{2} + (y - 0)^{2} = \frac{52}{4}

x^{2} + y^{2} = 10

x^{2} + 2 x + 10 + y^{2} - 6 y - 10 = 0

What is the circumference 2x^2+2y^2-24x+28y+120=0 ?
The circumference 2x^2+2y^2-24x+28y+120=0 is C=10pi