What is the circumference (x-3)^2+(y+4)^2=sqrt(8) ?

The circumference (x-3)^2+(y+4)^2=sqrt(8) is C=2\sqrt[4]{8}pi

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circumference (x-3)^2+(y+4)^2=sqrt(8)

circumference

(x - 3)^{2} + (y + 4)^{2} = 8

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 3)^{2} + (y + 4)^{2} = 8 : r = 8

C = 2 π 8

Refine

x^{2} + y^{2} - 6 y = 16

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0

x^{2} - 4 x + y^{2} + 2 y + 1 = 0

x^{2} - 6 x + y^{2} + 4 y + 4 = 0

What is the circumference (x-3)^2+(y+4)^2=sqrt(8) ?
The circumference (x-3)^2+(y+4)^2=sqrt(8) is C=2\sqrt[4]{8}pi