What is the circumference x^2+y^2-x-6y-5=0 ?

The circumference x^2+y^2-x-6y-5=0 is C=sqrt(57)pi

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circumference x^2+y^2-x-6y-5=0

circumference

x^{2} + y^{2} - x - 6 y - 5 = 0

C = 57 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - x - 6 y - 5 = 0 : r = \frac{57}{2}

C = 2 π \frac{57}{2}

Refine

C = 57 π

(x - 6)^{2} + (y + 5)^{2} = 64

x^{2} - 6 x + 2 y + y^{2} + 1 = 0

X^{2} + Y^{2} = 9

(x - 2)^{2} + (y + 3)^{2} = 11^{2}

x^{2} + y^{2} - 10 x + 6 y = 0

What is the circumference x^2+y^2-x-6y-5=0 ?
The circumference x^2+y^2-x-6y-5=0 is C=sqrt(57)pi