What is the circumference (x-1)^2+(y-1)^2=sqrt(18) ?

The circumference (x-1)^2+(y-1)^2=sqrt(18) is C=2\sqrt[4]{18}pi

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circumference (x-1)^2+(y-1)^2=sqrt(18)

circumference

(x - 1)^{2} + (y - 1)^{2} = 18

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 1)^{2} + (y - 1)^{2} = 18 : r = 18

C = 2 π 18

Refine

x^{2} + y^{2} + 4 x - 10 y + 11 = 0

(x - 1)^{2} + (y - 3)^{2} = 16

(x + 7)^{2} + (y - 2)^{2} = 81

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1

(x - 1)^{2} + (y - 3)^{2} = 25

What is the circumference (x-1)^2+(y-1)^2=sqrt(18) ?
The circumference (x-1)^2+(y-1)^2=sqrt(18) is C=2\sqrt[4]{18}pi