What is the circumference (x-4)^2+(y+2)^2=49 ?

The circumference (x-4)^2+(y+2)^2=49 is C=14pi

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circumference (x-4)^2+(y+2)^2=49

circumference

(x - 4)^{2} + (y + 2)^{2} = 49

C = 14 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 4)^{2} + (y + 2)^{2} = 49 : r = 7

C = 2 π 7

Refine

C = 14 π

x^{2} + y^{2} - 4 x = 0

x^{2} + y^{2} + 4 x - 2 y + 1 = 0

(x - 1)^{2} + y^{2} = 4

(x + 2)^{2} + (y - 1)^{2} = 25

x^{2} + (y - 3)^{2} = 20

What is the circumference (x-4)^2+(y+2)^2=49 ?
The circumference (x-4)^2+(y+2)^2=49 is C=14pi