What is the circumference x^2-3x+4y+y^2=16 ?

The circumference x^2-3x+4y+y^2=16 is C=sqrt(89)pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2-3x+4y+y^2=16

circumference

x^{2} - 3 x + 4 y + y^{2} = 16

C = 89 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} - 3 x + 4 y + y^{2} = 16 : r = \frac{89}{2}

C = 2 π \frac{89}{2}

Refine

C = 89 π

x^{2} + y^{2} + 4 x + 12 y + 3 = 0

9 x^{2} + 9 y^{2} - 6 x - 2 y - 11 = 0

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y - 11 = 0

x^{2} + y^{2} + 5 x + 20 y + 10 = 0

What is the circumference x^2-3x+4y+y^2=16 ?
The circumference x^2-3x+4y+y^2=16 is C=sqrt(89)pi