What is the circumference (x-1/2)^2+(y-3/2)^2=1 ?

The circumference (x-1/2)^2+(y-3/2)^2=1 is C=2pi

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circumference (x-1/2)^2+(y-3/2)^2=1

circumference

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1

C = 2 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1 : r = 1

C = 2 π 1

Refine

C = 2 π

x^{2} + y^{2} - 4 x + 6 y + 4 = 0

x^{2} + y^{2} - 6 x - 4 y + 9 = 0

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 13

(x - 8)^{2} + (y - 8)^{2} = 16

(x + 3)^{2} + (y - 1)^{2} = 1

What is the circumference (x-1/2)^2+(y-3/2)^2=1 ?
The circumference (x-1/2)^2+(y-3/2)^2=1 is C=2pi