What is the circumference (x-9)^2+(y+4)^2=25 ?

The circumference (x-9)^2+(y+4)^2=25 is C=10pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference (x-9)^2+(y+4)^2=25

circumference

(x - 9)^{2} + (y + 4)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 9)^{2} + (y + 4)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

16 x^{2} + 16 y^{2} - 48 x - 16 y - 41 = 0

x^{2} + y^{2} + 8 x + 2 y + 1 = 0

x^{2} + y^{2} + 14 y + 13 = 0

(x - 3)^{2} + (y - 2)^{2} = 25

x^{2} + (y - 1)^{2} = 1

What is the circumference (x-9)^2+(y+4)^2=25 ?
The circumference (x-9)^2+(y+4)^2=25 is C=10pi