What is the circumference (x+1)^2+(y+1)^2=13 ?

The circumference (x+1)^2+(y+1)^2=13 is C=2sqrt(13)pi

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circumference (x+1)^2+(y+1)^2=13

circumference

(x + 1)^{2} + (y + 1)^{2} = 13

C = 213 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y + 1)^{2} = 13 : r = 13

C = 213 π

(x - 3)^{2} + (y - 1)^{2} = 4

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

x^{2} + y^{2} \leq 4^{2}

(x - 4)^{2} + y^{2} = 8

x^{2} = - y^{2} + 4

What is the circumference (x+1)^2+(y+1)^2=13 ?
The circumference (x+1)^2+(y+1)^2=13 is C=2sqrt(13)pi