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diameter x^2+y^2<= 25

Solution

diameter

x^{2} + y^{2} \leq 25

Solution

d = 10

Solution steps

d = 2 r

Find the radius

Radius given

x^{2} + y^{2} \leq 25 : r = 5

d = 2 \cdot 5

Refine

d = 10

Popular Examples

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diameter x^2+y^2-6x+5=0 diameter

x^{2} + y^{2} - 6 x + 5 = 0

diameter (x-1.5)^2+(y+0.5)^2=110.5 diameter

(x - 1.5)^{2} + (y + 0.5)^{2} = 110.5

diameter x^2+y^2-2x-4y-31=0 diameter

x^{2} + y^{2} - 2 x - 4 y - 31 = 0

Frequently Asked Questions (FAQ)

What is the diameter x^2+y^2<= 25 ?
The diameter x^2+y^2<= 25 is d=10