en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^2+y^2-2x+4y-4=0

Solution

area

x^{2} + y^{2} - 2 x + 4 y - 4 = 0

Solution

A = 9 π

Solution steps

A = π r^{2}

Find the radius

Radius given

x^{2} + y^{2} - 2 x + 4 y - 4 = 0 : r = 3

A = π 3^{2}

Refine

A = 9 π

Popular Examples

area x^2+y^2= 7/pi area

x^{2} + y^{2} = \frac{7}{π}

area 16x^2+16y^2+32x+8y=47 area

16 x^{2} + 16 y^{2} + 32 x + 8 y = 47

area x^2+y^2-4x=0 area

x^{2} + y^{2} - 4 x = 0

area x^2+y^2= 25/36 area

x^{2} + y^{2} = \frac{25}{36}

area x^2+y^2-2x+6y+9=0 area

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

Frequently Asked Questions (FAQ)

What is the area x^2+y^2-2x+4y-4=0 ?
The area x^2+y^2-2x+4y-4=0 is A=9pi