What is 8x^2+2y^2-12=0 ?

The solution to 8x^2+2y^2-12=0 is Ellipse with (h,k)=(0,0),a=sqrt(3/2),b=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8x^2+2y^2-12=0

8 x^{2} + 2 y^{2} - 12 = 0

(h, k) = (0, 0), a = \frac{3}{2}, b = 6

Solution steps

8 x^{2} + 2 y^{2} - 12 = 0

Rewrite

8 x^{2} + 2 y^{2} - 12 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{3}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{3}{2}, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = \frac{3}{2}

x^{2} + 4 y^{2} + 2 x - 12 y + 2 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

\frac{( y + 2 ) ^{2}}{12} + \frac{x ^{2}}{2} - 1 = 0

x^{2} - x + 4 y^{2} + 24 y + 30 = 4

4 x^{2} + y^{2} = 2 y

What is 8x^2+2y^2-12=0 ?
The solution to 8x^2+2y^2-12=0 is Ellipse with (h,k)=(0,0),a=sqrt(3/2),b=sqrt(6)