What is (x^2)/(25)+(y^2)/(169)=1 ?

The solution to (x^2)/(25)+(y^2)/(169)=1 is Ellipse with (h,k)=(0,0),a=5,b=13

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(x^2)/(25)+(y^2)/(169)=1

\frac{x ^{2}}{25} + \frac{y ^{2}}{169} = 1

(h, k) = (0, 0), a = 5, b = 13

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{169} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{169} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{1 3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 13

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 13, a = 5

9 x^{2} + 25 y^{2} = 25

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 4 ) ^{2}}{4} = 1

5 x - 2 x^{2} - 5 y - 5 y^{2} + 8 = 0

\frac{( x - 1 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{36} = 1

9 x^{2} + 16 y^{2} = 1

What is (x^2)/(25)+(y^2)/(169)=1 ?
The solution to (x^2)/(25)+(y^2)/(169)=1 is Ellipse with (h,k)=(0,0),a=5,b=13