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Popular >

16x^2+25y^2=1

Solution

16 x^{2} + 25 y^{2} = 1

Solution

(h, k) = (0, 0), a = \frac{1}{4}, b = \frac{1}{5}

Solution steps

16 x^{2} + 25 y^{2} = 1

Rewrite

16 x^{2} + 25 y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{1}{4}, b = \frac{1}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{1}{4}, b = \frac{1}{5}

Popular Examples

4x^2+2y^2-8x+12y+6=0

4 x^{2} + 2 y^{2} - 8 x + 12 y + 6 = 0

((x+3)^2)/(25)+((y-8)^2)/(16)=1

\frac{( x + 3 ) ^{2}}{25} + \frac{( y - 8 ) ^{2}}{16} = 1

16x^2+9y^2-36y=108

16 x^{2} + 9 y^{2} - 36 y = 108

3x^2+12y^2-6x-48y+33=0

3 x^{2} + 12 y^{2} - 6 x - 48 y + 33 = 0

x^{(2)}+4y^{(2)}+2x-12y+6=0

x^{(2)} + 4 y^{(2)} + 2 x - 12 y + 6 = 0

Frequently Asked Questions (FAQ)

What is 16x^2+25y^2=1 ?
The solution to 16x^2+25y^2=1 is Ellipse with (h,k)=(0,0),a= 1/4 ,b= 1/5