What is ((x-1)^2)/(5^2)+((y+1)^2)/(3^2)=1 ?

The solution to ((x-1)^2)/(5^2)+((y+1)^2)/(3^2)=1 is Ellipse with (h,k)=(1,-1),a=5,b=3

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((x-1)^2)/(5^2)+((y+1)^2)/(3^2)=1

\frac{( x - 1 ) ^{2}}{5 ^{2}} + \frac{( y + 1 ) ^{2}}{3 ^{2}} = 1

(h, k) = (1, - 1), a = 5, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{5 ^{2}} + \frac{( y + 1 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 1), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, - 1), a = 5, b = 3

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{4} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{16} = 1

4 = 36 - 9 x^{2} - 4 y^{2}

9 x^{2} + 25 y^{2} - 18 x - 100 y - 116 = 0

\frac{x ^{2}}{8} + \frac{y ^{2}}{5} = 1

What is ((x-1)^2)/(5^2)+((y+1)^2)/(3^2)=1 ?
The solution to ((x-1)^2)/(5^2)+((y+1)^2)/(3^2)=1 is Ellipse with (h,k)=(1,-1),a=5,b=3