What is (x^2)/(49)+(y^2)/(81)=1 ?

The solution to (x^2)/(49)+(y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=7,b=9

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(x^2)/(49)+(y^2)/(81)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

(h, k) = (0, 0), a = 7, b = 9

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 9, a = 7

3 x^{2} + 5 y^{2} - 6 x + 2 y - 9 = 0

9 x^{2} + 25 y^{2} + 18 x - 100 y - 116 = 0

\frac{x ^{2}}{24} + \frac{y ^{2}}{9} = 1

9 x^{2} + 25 y^{2} - 36 x + 50 y - 164 = 0

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{4} - 1 = 0

What is (x^2)/(49)+(y^2)/(81)=1 ?
The solution to (x^2)/(49)+(y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=7,b=9