What is ((x+2)^2)/4+((y-7)^2)/(49)=1 ?

The solution to ((x+2)^2)/4+((y-7)^2)/(49)=1 is Ellipse with (h,k)=(-2,7),a=2,b=7

Popular >

((x+2)^2)/4+((y-7)^2)/(49)=1

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 7 ) ^{2}}{49} = 1

(h, k) = (- 2, 7), a = 2, b = 7

Solution steps

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 7 ) ^{2}}{49} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 7 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} + \frac{( y - 7 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 7), a = 2, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 7), b = 7, a = 2

\frac{( x - 2 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{16} = 1

25 x^{2} + 16 y^{2} - 250 x - 32 y + 241 = 0

9 x^{2} + 5 y^{2} = 45

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

25 x^{2} + 12 y^{2} + 20 x - 12 y = 4

What is ((x+2)^2)/4+((y-7)^2)/(49)=1 ?
The solution to ((x+2)^2)/4+((y-7)^2)/(49)=1 is Ellipse with (h,k)=(-2,7),a=2,b=7