What is (x^2)/(49)+(y^2)/(64)=1 ?

The solution to (x^2)/(49)+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=7,b=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(49)+(y^2)/(64)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 7, b = 8

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 7

4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0

4 (x - 5)^{2} + 9 (y + 2)^{2} = 36

3 x^{2} + 4 y^{2} - 28 x - 16 y + 48 = 0

4 x^{2} + 8 x + 9 (y - 2)^{2} = 32

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{16} = 1

What is (x^2)/(49)+(y^2)/(64)=1 ?
The solution to (x^2)/(49)+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=7,b=8