What is ((x-1)^2}{16}+\frac{(y-0)^2)/9 =1 ?

The solution to ((x-1)^2}{16}+\frac{(y-0)^2)/9 =1 is Ellipse with (h,k)=(1,0),a=4,b=3

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((x-1)^2}{16}+\frac{(y-0)^2)/9 =1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 0 ) ^{2}}{9} = 1

(h, k) = (1, 0), a = 4, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 0 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 0 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 0), a = 4, b = 3

15 x^{2} + 16 y^{2} = 240

4 y^{2} + 9 x^{2} = 36

2 x^{2} + 3 y^{2} + 12 x = 10

\frac{( x - 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x + 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{16} = 1

What is ((x-1)^2}{16}+\frac{(y-0)^2)/9 =1 ?
The solution to ((x-1)^2}{16}+\frac{(y-0)^2)/9 =1 is Ellipse with (h,k)=(1,0),a=4,b=3