What is 8x^2+28y^2=112 ?

The solution to 8x^2+28y^2=112 is Ellipse with (h,k)=(0,0),a=sqrt(14),b=2

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8x^2+28y^2=112

8 x^{2} + 28 y^{2} = 112

(h, k) = (0, 0), a = 14, b = 2

Solution steps

8 x^{2} + 28 y^{2} = 112

Rewrite

8 x^{2} + 28 y^{2} = 112

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 14 ) ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 14, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 14, b = 2

\frac{x ^{2}}{9} + \frac{( y + 3 ) ^{2}}{16} = 1

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0

2 x^{2} + 3 y^{2} = 10

4 x^{2} + y^{2} - 8 x - 4 y - 8 = 0

9 x^{2} + 16 y^{2} + 126 x + 96 y + 441 = 0

What is 8x^2+28y^2=112 ?
The solution to 8x^2+28y^2=112 is Ellipse with (h,k)=(0,0),a=sqrt(14),b=2